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[Guest guest]

Dear Jain Sir,

My last message may have been little bit confusing. I have felt that I have not

been able to explain clearly. There may be some errors. Hence I wanted to

clarify regarding the retrogression of nodes and the rate of retrogression. It

is however a back calculation or a justification. You may omit reading the last

message if confusing.

Data taken from Raman’s Ephemeris.

Time Date  Transit of Moon Transit of Kethu

7-45 AM 2-08-2008 116-29 116-28

20-45 PM 31-08-2008 141-45 114-55

First date was selected as solar eclipsed took place on that date date and time

according to the said ephemeris.

Second time and date was selected since it falls after 29 days and 13 hours

after the first date. Moon takes this time to make a complete revolution around

the earth and expected to cross the ecliptic. 

The Moon would have crossed at 116-29 conjoining Kethu had the Earth no

revolution. Since the Earth revolves the zodiac moves and Moon crosses at 141-45

degrees on 31st August.

Moon on 31st August  at  141-45

Moon on 2nd August   at  116-29

Difference                   =    25-16

On the first date the Moon and Kethu were almost at the same point. A difference

of 1 minute may be ignored.

But on 2nd date : -

Moon was at                    141-45

Kethu was at                    114-55

Kethu was back by             26-50 degrees and minutes.

But Moon moved during this period for 25 degrees and 16 minutes.

When we deduct the Moon’s movement from the lag of Kethu we get a difference

of one minute and 34 seconds. This is the retrogression of Kethu in 29 days and

13 hours.when we calculate the rate /day it comes to 3’ 11’’.

This is how the retrogression and the rate can be justified.

Dr. Luther