Guest guest Posted October 16, 2003 Report Share Posted October 16, 2003 ~ Om Namah Shivaya ~ Respected Narshima Ji, Namaste Thanks for explaining. How foolish of me, it was so simple concept, when we are dividing by 12, how can I get 12 as remainder. Not using my common sense this time. Will try to be more active next time. Thanks for clarifying my doubt. regards, Neeraj Gupta --- "Narasimha P.V.R. Rao" <pvr wrote: > Namaste Neeraj, > > If the remainder is 0, take it as 12. > > Basically, today's counting is 0-based. If you > divide 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, > 14 etc by 12, you get 0, 1, 2, ... , 11, 0, 1, ... > etc as the remainder. In the days of Parasara, > counting was 1-based. If you divide 1, 2, 3, 4, 5, > 6, 7, 8, 9, 10, 11, 12, 13, 14 etc by 12, you get 1, > 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, ... etc as > the remainder. > > May Jupiter's light shine on us, > Narasimha > > > ~ Om Namah Shivaya ~ > > > > Respected Gurus and Senior Members, > > > > While calculating Sayanaadi Avastha, if the > remainder > > turns out to be 0, then what should be inferred. > > > > i.e. [(C X P X A )+ M + G + L ] / 12 > > > > So if this remainder comes out to be 0, what > Sayanaadi > > Avastha will it become, as Avastha Index are given > > from 1 to 12. > > > > > > Kindly answer my query. > > > > regards, > > > > Neeraj Gupta > > ===== http://www.geocities.com/master_minds_india/ The New with improved product search Quote Link to comment Share on other sites More sharing options...
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